How to display image/widget in the current active screen upon receiving an event from backend?

[KNara.2]

How to display image/widget in the current active screen upon receiving an event from backend?

Hi,

Let's say we have 10 screens and we need to make a image/widget visible when an event is received from backend.

Can it be done this way?

In model.cpp 

whenever the event is receieved 

static_cast<FrontendApplication*>(touchgfx::Application::getInstance())->handleTickEvent();

and in Screen1View.cpp

void Screen1View::setupScreen()

{

    Screen1ViewBase::setupScreen();

    displayIcon();

}

void Screen1View::displayIcon()

{

uint8_t status = Screen1ViewBase::presenter->GetStatus(); //Read the status received along with the event

if(status == 0x00)

{

IconImage.setVisible(true);

IconImage.invalidate();

}

}

void Screen1View::handleTickEvent()

{

displayIcon();

}

My question is - Does it create overhead in handleTickEvent of each screen to repeatedly read the status from model?

[Yoann KLEIN]

Hello @KNara.2,

I think what you propose should be doable without issues, since handleTickEvent() will only be used for the active Screen.

If you need more insights about how to use the Model-View-Presenter pattern within TouchGFX, you can read the documentation. There are also many posts treating similar topics in this forum, like this one.