TIM5 interrupt goes to default handler

[patrickbrataas9]

Posted on February 05, 2014 at 23:54

I have just implementet a Low Speed Internal (LSI) oscillator calibration using a timer connected to the High Speed External (HSI) crystal. Right after I enabled the timer interrupt (and probably interrupt fires) I get redirected to the Default_Handler(). I can't see anything wrong with my code and hope someone could review it.

After enabling LSI clock and waiting for it to stabilize:

//Enable the Low Speed Internal oscillator. 
RCC_LSICmd(ENABLE); 
//Wait for LSI to stabilize. 
while(RCC_GetFlagStatus(RCC_FLAG_LSIRDY) == RESET);

The LSI calibration function is called:

void LSI_Calibrate(void) 
{ 
NVIC_InitTypeDef NVIC_InitStructure; 
TIM_ICInitTypeDef TIM_ICInitStructure; 
//Enable Timer 5 clock. 
RCC_APB1PeriphClockCmd(RCC_APB1Periph_TIM5, ENABLE); 
//Register interrupt with Nested Vectored Interrupt Controller (NVIC). 
NVIC_InitStructure.NVIC_IRQChannel = TIM5_IRQn; 
NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 0; 
NVIC_InitStructure.NVIC_IRQChannelSubPriority = 0; 
NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE; 
NVIC_Init(&NVIC_InitStructure); 
//Set Timer 5 prescaler. 
TIM_PrescalerConfig(TIM5, 0, TIM_PSCReloadMode_Immediate); 
//Connect LSI clock output to Timer 5 channel 4 input capture. 
GPIO_PinRemapConfig(GPIO_Remap_TIM5CH4_LSI, ENABLE); 
//Configure Timer 5 as input capture. 
TIM_ICInitStructure.TIM_Channel = TIM_Channel_4; 
TIM_ICInitStructure.TIM_ICPolarity = TIM_ICPolarity_Rising; 
TIM_ICInitStructure.TIM_ICSelection = TIM_ICSelection_DirectTI; 
TIM_ICInitStructure.TIM_ICPrescaler = TIM_ICPSC_DIV8; 
TIM_ICInitStructure.TIM_ICFilter = 0; 
TIM_ICInit(TIM5, &TIM_ICInitStructure); 
//Reset Timer 5 counter. 
timer5Counter = 0; 
//Clear all interrupt flags. 
TIM5->SR = 0; 
//Enable channel 4. 
TIM_CCxCmd(TIM5, TIM_Channel_4, TIM_CCx_Enable); 
//Enable Timer 5 capture compare channel 4 interrupt. 
TIM_ITConfig(TIM5, TIM_IT_CC4, ENABLE); 
//Reset Timer 5. 
TIM_SetCounter(TIM5, 0); 
//Enable global interrupt. 
__enable_irq(); 
//Enable Timer 5. 
TIM_Cmd(TIM5, ENABLE); 
//Wait for LSI calibration to finish. 
while(timer5Counter < 2); 
//Disable Timer 5 capture compare channel 4 interrupt. 
TIM_ITConfig(TIM5, TIM_IT_CC4, DISABLE); 
//Disable global interrupt. 
__disable_irq(); 
//Disconnect LSI clock output to Timer 5 channel 4 input capture. 
GPIO_PinRemapConfig(GPIO_Remap_TIM5CH4_LSI, DISABLE); 
}

#interrupts

[Tesla DeLorean]

Posted on February 06, 2014 at 01:24

I don't see the handler.

Look at the handler, look at the linkage for the IRQHandler in the vector table, confirm it is there, and points to your handler. If using C++ consider if the name is mangled. Consider if you are using the right startup_stm32fxxx.sNot sure of your processor. Shouldn't really need to enable/disable global interrupt.

[patrickbrataas9]

Posted on February 06, 2014 at 02:10

I pressed ''open declaration'' on the ISR handler name and nothing happend. Rechecked the declarations and found out it was supposed to be TIM5_IRQHandler(), but mine was a copy paste mistake from my TIM1 (Advanced timer), which was then wrongly renamed to TIM5_CC_IRQHandler().

Thanks you clive1, again! =) I am enabling/disabling interrupt because this function is called at the very first of my program before all peripheral initialization. The interupts are enabled again before the main program loop.